Swagger⼊参为List
今天遇到⼀个奇葩的需求，为了⽅便，service的⼀个接⼝⼊参是List<Map>
repayMoney（List<Map<String,Object>）
那，我为了在controller调⽤service，⼊参类型得⼀致呀，
那么问题来了，controller⼊参也得是List吧，或者是其他形式的数据，转换为List<Map>
翻遍了整个项⽬，没看到之前有⼈swagger的controller⾥⼊参是List的，⽽且查了⼀下，
⽤@ApiImplicitParams注解的话，⼊参只能是String或者Integer，啊，这可怎么办，类似于这样
关注点在⼊参为List，这个测试写的不完善，⼤家只要关注⼊参就可以了
@ApiOperation(value = "测试")
@RequestMapping(value = "/sanbiaoRepaymentAmount",method = RequestMethod.POST)
@ApiImplicitParams({@ApiImplicitParam(name = "idCard", dataType = "String", value = "⾝份证号", pa
ramType = "query", required = true),            @ApiImplicitParam(name = "userNo", dataType = "Integer", value = "编号", paramType = "query", required = true),
@ApiImplicitParam(name = "onePeriodAmount", dataType = "String", value = "⾦额", paramType = "query", required = true)})
@ResponseBody
public Result sanbiaoRepaymentAmount(@RequestParam(value = "idCard", required = true) String idCard,
@RequestParam(value = "userNo", required = true) Integer userNo,
@RequestParam(value = "onePeriodAmount", required = true) String onePeriodAmount) {
Result result = new ResultSupport();
List<Map<String,Object>> repayList = new ArrayList<Map<String,Object>>();
Map paramMap = new HashMap();
paramMap.put("idCard",idCard);
paramMap.put("userNo",userNo);
paramMap.put("onePeriodAmount",onePeriodAmount);
repayList.add(paramMap);
return result;
}
好吧，查了⼀下，好像去掉ApiImplicitParams，就可以传list，
于是我做了如下修改
@ApiOperation(value = "测试")
@RequestMapping(value = "/sanbiaoRepaymentAmount",method = RequestMethod.POST)
@ResponseBody
public Result sanbiaoRepaymentAmount(@RequestParam(value = "idCardList", required = true) List<String> idCardList,
@RequestParam(value = "userNoList", required = true) List<Integer> userNoList,
@RequestParam(value = "onePeriodAmountList", required = true) List<String> onePeriodAmountList) {
Result result = new ResultSupport();
List<Map<String,Object>> repayList = new ArrayList<Map<String,Object>>();
Map paramMap = new HashMap();
for(int i=0; i<idCardList.size(); i++){
//因为这⾥⼗分确定，三个⼊参list的长度是⼀致的，所以，在这⾥，把三个List对应的下标参数放在map⾥
paramMap.put("idCard",(i));
paramMap.put("userNo",(i));
param nameparamMap.put("onePeriodAmount",(i));
repayList.add(paramMap);
}
System.out.println("haha");
System.out.println(repayList);
    System.out.Class());
return result;
}
开始测试--Swagger⼊参是这样得，看吧，DataType 是Array，数组呗
逗号分隔参数，就可以咯
顺利经过测试，能⾛到repayMoney()

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