学⽣各门课程成绩统计SQL语句⼤全
学⽣成绩表(stuscore)：
姓名：name课程：subject分数：score学号：stuid
张三数学891
张三语⽂801
张三英语701
李四数学902
李四语⽂702
李四英语802
创建表
SET ANSI_NULLS ONGOSET QUOTED_IDENTIFIER ONGOSET ANSI_PADDING ONGOCREATE T
ABLE [dbo].[stuscore](    [name] [varchar](50) COLLATE Chinese_PRC_CI_AS NULL,    [subject] [varchar](50) COLLATE Chinese_PRC_CI_A
问题：
1.计算每个⼈的总成绩并排名(要求显⽰字段：姓名，总成绩)
2.计算每个⼈的总成绩并排名(要求显⽰字段: 学号，姓名，总成绩)
3.计算每个⼈单科的最⾼成绩(要求显⽰字段: 学号，姓名，课程，最⾼成绩)
update语法大全4.计算每个⼈的平均成绩（要求显⽰字段: 学号，姓名，平均成绩）
5.列出各门课程成绩最好的学⽣(要求显⽰字段: 学号，姓名，科⽬，成绩)
6.列出各门课程成绩最好的两位学⽣(要求显⽰字段: 学号，姓名，科⽬，成绩)
7.如下：
学号姓名语⽂数学英语总分平均分
8．列出各门课程的平均成绩（要求显⽰字段：课程，平均成绩）
9．列出数学成绩的排名（要求显⽰字段：学号，姓名，成绩，排名）
10．列出数学成绩在2-3名的学⽣（要求显⽰字段：学号，姓名，科⽬，成绩）
11．求出李四的数学成绩的排名
12．如下：
课程不及格（0-59）个良（60-80）个优（81-100）个
13．如下：数学：张三(50分)，李四(90分)，王五(90分)，赵六(76分)
答案：
1.计算每个⼈的总成绩并排名
select name,sum(score) as allscore from stuscore group by name order by allscore
2.计算每个⼈的总成绩并排名
select distinct t1.name,t1.stuid,t2.allscore from  stuscore t1,(    select stuid,sum(score) as allscore from stuscore group by stuid)t2where t1.stuid=t2.stuidorder by t2.allscore desc
3. 计算每个⼈单科的最⾼成绩
select t1.stuid,t1.name,t1.subject,t1.score from stuscore t1,(select stuid,max(score) as maxscore from stuscore group by stuid) t2where t1.stuid=t2.stuid and t1.score=t2.maxscore
4.计算每个⼈的平均成绩
select distinct t1.stuid,t1.name,t2.avgscore from stuscore t1,(select stuid,avg(score) as avgscore from stuscore group by stuid) t2where t1.stuid=t2.stuid
5.列出各门课程成绩最好的学⽣
select  t1.stuid,t1.name,t1.subject,t2.maxscore from stuscore t1,(select subject,max(score) as maxscore from stuscore group by subject) t2where t1.subject=t2.subject and t1.score=t2.maxscore
6.列出各门课程成绩最好的两位学⽣
select distinct t1.* from stuscore t1 where t1.id in (select top 2 stuscore.id from stuscore where subject = t1.subject order by score desc) order by t1.subject
7.学号姓名语⽂数学英语总分平均分
select stuid as 学号,name as 姓名,sum(case when subject='语⽂' then score else 0 end) as 语⽂,sum(case when subject='数学' then score else 0 end) as 数学,sum(case when subject='英语' then score else 0 end) as 英语,sum(score) as 总分,(su
8.列出各门课程的平均成绩
select subject,avg(score) as avgscore from stuscoregroup by subject
9.列出数学成绩的排名
declare @tmp table(pm int,name varchar(50),score int,stuid int)insert into @tmp select null,name,score,stuid from stuscore where subject='数学' order by score descdeclare @id intset @id=0;update @tmp set @id=@id+1,pm=@idselect * from @ select  DENSE_RANK () OVER(order by score desc) as row,name,subject,score,stuid from stuscore where subject='数学'order by score desc
10. 列出数学成绩在2-3名的学⽣
select t3.*  from(select top 2 t2.*  from (select top 3 name,subject,score,stuid from stuscore where subject='数学'order by score desc) t2 order by t2.score) t3 order by t3.score desc
11. 求出李四的数学成绩的排名
declare @tmp table(pm int,name varchar(50),score int,stuid int)insert into @tmp select null,name,score,stuid from stuscore where subject='数学' order by score descdeclare @id intset @id=0;update @tmp set @id=@id+1,pm=@idselect * from @
12. 课程不及格（-59）良（-80）优（-100）
select subject, (select count(*) from stuscore where score<60 and subject=t1.subject) as 不及格,(select count(*) from stuscore where score between 60 and 80 and subject=t1.subject) as 良,(select count(*) from stuscore where score >80 and su
13. 数学：张三(50分)，李四(90分)，王五(90分)，赵六(76分)
declare @s varchar(1000)set @s=''select @s =@s+','+name+'('+convert(varchar(10),score)+'分)' from stuscore where subject='数学' set @s=stuff(@s,1,1,'')print '数学:'+@s

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