java解析复杂的xml⽂件_Java解析复杂xml⽂件，使⽤Xpath Java解析复杂xml⽂件，需要使⽤到xpath，⾸先使⽤了Jdom2。代码⽰例如下：
public static Document GetFileFromLocal(String filename){
try {
FileInputStream stream=new FileInputStream(String.format("d:/x下载/%s.xml", filename));
SAXBuilder saxBuilder = new SAXBuilder();
Document doc = saxBuilder.build(stream);
return doc;
} catch (FileNotFoundException e) {
e.printStackTrace();
} catch (JDOMException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
java xml是什么}
return null;
}
但是该xml解析器，不⽀持xpath。所以修改为dom4j。在l⽂件⾥⾯添加依赖，maven会⾃动下载该jar⽂件：
org.dom4j
dom4j
2.1.0
解析xml代码⽰例如下:
public class XmlHelper {
public static Document parse(String url) {
SAXReader reader = new SAXReader();
Document document = null;
try {
document = ad(url);
} catch (DocumentException e) {
e.printStackTrace();
}
return document;
}
public static Element getRootElement(String url){
SAXReader reader = new SAXReader();
Document document = null;
try {
document = ad(url);
} catch (DocumentException e) {
e.printStackTrace();
}
RootElement();
}
public static Element getXmlElement(Element rootNode, String xpath) { if(rootNode==null||xpath==""){
return null;
}
return rootNode.element(xpath);
}
public static String getXmlNodeText(Element rootNode, String xpath) { if(rootNode==null||xpath==""){
return null;
}
Element element= rootNode.element(xpath);
if(element==null){
return "";
}
Text();
}
}

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