使⽤AJAX（包含正则表达式）验证⽤户登录的步骤我们来分⼀下步骤吧：
1.HTML代码，页⾯先写出来；
2.正则表达式验证输⼊的⽤户名密码是否正确，失去焦点验证
3.Ajax异步提交
4.servlet这是后台处理代码获取数据并对⽐响应，然后跳转成功页⾯
效果图：
结构：
代码如下：
<%@ page language="java" import="java.util.*" pageEncoding="utf-8"%>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<script type="text/javascript" src="JS/jQuery.js"></script>
<style type="text/css">
table {
width: 360px;
height: 45px:
text-align: center;
margin-top: 120px;
border-collapse: collapse;
}
input {
width: 280px;
height: 30px;
}
</style>
</head>
<body>
<form action="#" method="post">
<center>
<table align="center" border="1">
<tr>
<td>⽤户名:</td>
<td><input type="text" name="name" id="username"
onblur="verifyName()" /></td>
</tr>
<tr>
<td>密码:</td>
<td><input type="text" name="pwd" id="mypwd"
onblur="verifyPwd()" /></td>
</tr>
<tr>
<td colspan="3" align="center" height="36px"><input
type="button" value="提交登录验证" /></td>
</tr>
</table>
</center>
</form>
<script type="text/javascript">
function verifyName() {
//⽤户名校验
var verifyName = ElementById("username").value;
var name = /^[A-Z][0-9A-Za-z_][a-zA-Z0-9_]{5,19}$/; // ⼤写字母开头 6-20位字符(不允许有符号但是允许有_)
if (!st(verifyName)) {
//$("#username").after("<span>⼤写字母开头6-20位字符(不允许有符号但是允许有_)</span>");
$("#username").css("border-color", "red");
return false;
} else {
return true;
}
}
function verifyPwd() {
//密码
var verifyPwd = ElementById("mypwd").value;
var pwd = /^[A-Z][A-Za-z0-9]\w{7,14}.{1,20}$/; //⼤写开头数字字母符号混合 8-15位
if (!st(verifyPwd)) {
$("#username").css("border-color", "red");
return false;
} else {
return true;
}
}
$(function() {
$(":button").on("click", function() {
$.ajax({
type : "post",
url : "AJAXServlet",
data : {
name : $("#username").val(),
pwd : $("#mypwd").val()
},
dataType : "text",
success : function(data) {
if (data == "ok") {
window.location.href = "show.jsp";
} else {
alert("登录失败！");
$("#mypwd").val("");
$("#username").focus().select();
}
}
});
});
});
</script>
</body>
</html>
servlet代码：
package com.chaz.servlet;
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class AJAXServlet extends HttpServlet {
public void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { doPost(request, response);
}
html实现用户注册登录代码public void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { response.setContentType("text/html;charset=utf-8");
request.setCharacterEncoding("utf-8");
PrintWriter out = Writer();
String name = "ZhangSan";
String pwd = "Zhang123456";
String ajaxName = Parameter("name");
String ajaxPwd = Parameter("pwd");
System.out.println(ajaxName+":"+ajaxPwd);
if(name.equals(ajaxName)&&pwd.equals(ajaxPwd)){
out.print("ok");
}else{
out.print("Error");
}
out.flush();
out.close();
}
}
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="3.0"
xmlns="java.sun/xml/ns/javaee"
xmlns:xsi="/2001/XMLSchema-instance"
xsi:schemaLocation="java.sun/xml/ns/javaee java.sun/xml/ns/javaee/web-app_3_0.xsd">
<servlet>
<description>This is the description of my J2EE component</description>
<display-name>This is the display name of my J2EE component</display-name>
<servlet-name>AJAXServlet</servlet-name>
<servlet-class>com.chaz.servlet.AJAXServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>AJAXServlet</servlet-name>
<url-pattern>/AJAXServlet</url-pattern>
</servlet-mapping>
</web-app>
跳转成功页⾯就这个 ：
<body> 登录成功！</body>
总结
以上所述是⼩编给⼤家介绍的使⽤AJAX（包含正则表达式）验证⽤户登录的步骤，希望对⼤家有所帮助，如果⼤家有任何疑问请给我留⾔，⼩编会及时回复⼤家的。在此也⾮常感谢⼤家对⽹站的⽀持！
如果你觉得本⽂对你有帮助，欢迎转载，烦请注明出处，谢谢！
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