splint的使用（代码示例）
1.空引用错误
在引用没有指向任何内存地址的指针时,会导致这种错误.也就是使用了一个没有赋值的指针.
splint支持一种特别的注释.这种注释写在C程序代码中,用于对程序进行特殊说明.
如下面这段程序.使用了/*@null@*/进行了说明,表示说明*s的值可能会是NULL.
//null.c
char firstChar1 (/*@null@*/ char *s)
{
return *s;
}
char firstChar2 (/*@null@*/ char *s)
{
if (s ==NULL) return '\0';
return *s;
}
//END
使用splint扫描这个程序时,会输出:
# splint null.c
Splint 3.1.1 --- 28 Apr 2005
null.c: (in function firstChar1)
null.c:3:11: Dereference of possibly null pointer s: *s
  null.c:1:35: Storage s may become null
Finished checking --- 1 code warning found
由于firstChar1和firstChar2都使用了null说明,表示指针s可能是个NULL值.
所以,splint会对s值的使用情况进行检查.因为firstChar2函数中,对s的值进行
了NULL的判断.所以,没有对firstChar2函数的指针s输出警告信息.
2.未定义的变量错误
C语言中,要求先定义变量,而后才可使用.所以,当使用一个没有定义的变量时,编译就会出错.
如下例,使用/*@in@*/说明的变量,表示必须进行定义.使用/*@out@*/说明的变量,表示在 执行过此函数后,这个变量就进行了定义.
// usedef.c
extern void setVal (/*@out@*/ int *x);
extern int getVal (/*@in@*/ int *x);
extern int mysteryVal (int *x);
int dumbfunc (/*@out@*/ int *x, int i)
{
if (i > 3) return *x;
else if (i > 1)
  return getVal (x);
else if (i == 0)
  return mysteryVal (x);
else
  {
setVal (x);
return *x;
  }
}
// END
使用splint检查usedef.c
$ splint usedef.c
Splint 3.1.1 --- 28 Apr 2005
usedef.c: (in function dumbfunc)
usedef.c:7:19: Value *x used before definition
  An rvalue is used that may not be initialized to a value on some execution
  path. (Use -usedef to inhibit warning)
usedef.c:9:18: Passed storage x not completely defined (*x is undefined):
                  getVal (x)
  Storage derivable from a parameter, return value or global is not defined.
  Use /*@out@*/ to denote passed or returned storage which need not be defined.
  (Use -compdef to inhibit warning)
usedef.c:11:22: Passed storage x not completely defined (*x is undefined):
                  mysteryVal (x)
Finished checking --- 3 code warnings
//错误原因: 由于程序中没有对x进行定义,所以报未定义错误.但setVal()使用了/*@out@*/说明,所以
在setVal(x);和return x;中,没有报未定义错误.
3.类型错误
C语言中的数据类型较多,各个之间有些细微差别.splint也可以对变量类型进行检查.
示例1:
//bool.c
int f (int i, char *s,bool b1, bool b2)
{
if (i = 3) return b1;
if (!i || s) return i;
if (s) return 7;
if (b1 == b2)
return 3;
怎么写代码做软件
return 2;
}
//END
使用splint进行检查:
$ splint bool.c
Splint 3.1.1 --- 28 Apr 2005
bool.c: (in function f)
bool.c:4:5: Test expression for if is assignment expression: i = 3
  The condition test is an assignment expression. Probably, you mean to use ==
  instead of =. If an assignment is intended, add an extra parentheses nesting
  (e.g., if ((a = b)) ...) to suppress this message. (Use -predassign to
  inhibit warning)
// 错误原因: if语句中的条件表达式是一个赋值语句.
bool.c:4:5: Test expression for if not boolean, type int: i = 3
  Test expression type is not boolean or int. (Use -predboolint to inhibit
  warning)
// 错误原因: if语句中的条件表达式的返回值,不是布尔型,而是整型.
bool.c:4:8: Return value type bool does not match declared type int: b1
  Types are incompatible. (Use -type to inhibit warning)
// 错误原因: 返回值是布尔型,而不是整型.
bool.c:5:6: Operand of ! is non-boolean (int): !i
  The operand of a boolean operator is not a boolean. Use +ptrnegate to allow !
  to be used on pointers. (Use -boolops to inhibit warning)
// 错误原因: "!"操作符的操作数不是布尔型,而是整型i.
bool.c:5:11: Right operand of || is non-boolean (char *): !i || s
// 错误原因: "||"操作符的右操作数不是布尔型,而是字符指针.
bool.c:7:5: Use of == with boolean variables (risks inconsistency because of
                multiple true values): b1 == b2
  Two bool values are compared directly using a C primitive. This may produce
  unexpected results since all non-zero values are considered true, so
  different true values may not be equal. The file bool.h (included in
  splint/lib) provides bool_equal for safe bool comparisons. (Use -boolcompare
  to inhibit warning)
// 错误原因: 使用"=="对两个布尔型进行比较.应该使用"&&".
Finished checking --- 6 code warnings
示例2:
//malloc1.c
#include <stdlib.h>
#include <stdio.h>
int main(void)
{
char *some_mem;
int size1=1048576;
some_mem=(char *)malloc(size1);
printf("Malloed 1M Memory!\n");
free(some_mem);
exit(EXIT_SUCCESS);
}
//END
使用splint检查malloc1.c
$ splint malloc1.c
Splint 3.1.1 --- 28 Apr 2005
malloc1.c: (in function main)
malloc1.c:9:25: Function malloc expects arg 1 to be size_t gets int: size1
  To allow arbitrary integral types to match any integral type, use
  +matchanyintegral.
Finished checking --- 1 code warning
修改变量size1的定义为:
size_t size1=1048576;
再使用splint进行检查.
$ splint malloc1.c

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