General Chemistry Examination (1)
首页选择题填空题判断题简答题计算题参考答案
I. There are 20 Questions. Circle your answer clearly; otherwise no credit will be given. Circle only one
answer. If you circle two or more, you    will receive no credit.
1. Choose the electron configurations that are not possible from among the following.  (    )
(a) 1s22s32p6  (b) 1s22s22p4  (c) 1s22s22p83s23p63d7  (d) 1s22s22p63s13d9
A. (a)(c)(d)
B. (a)
C. (a)(d)
D. (a)(c)
E. (c)(d)
2．A 0.40-g sample of a polypeptide dissolved in 1.0L of an aqueous solution at 27°C has an osmotic
pressure of 499Pa. What is the molar mass of the polypeptide? (    )
A. 2.0g⋅mol-1
B. 2.0×10-3 g⋅mol-1
C. 2.0×103 g⋅mol-1
D. 2.0×1023 g⋅mol-1
E. 2.0×10-2 g⋅mol-1
3. Raw milk sours in about 4 h at 28°C but in about 48 h in a refrigerator at 5°C. What is the activation
energy for the souring of milk?                    (    )
A. 75kJ⋅mol-1
B. 75J⋅mol-1
C. 150kJ⋅mol-1
D. 150J⋅mol-1
（E）none of above is correct
4. Which of following solutions can not be used as buffer solution?      (    )
A. 50mL 0.1mol⋅L-1 KH2PO4 solution + 50mL 0.1 mol⋅L-1 Na2HPO4 solution
B. 50mL 0.1 mol⋅L-1 HAc solution + 50mL 0.1 mol⋅L-1 NaOH solution
C. 50mL 0.1 mol⋅L-1 NH3 solution + 50mL 0.1 mol⋅L-1 NH4Cl solution
D. 50mL 0.1 mol⋅L-1 Na2CO3 solution + 50mL 0.1 mol⋅L-1 NaHCO3 solution
E. 50mL 0.1 mol⋅L-1 HAc solution + 50mL 0.1 mol⋅L-1 Na Ac solution
5. In a neuron (a nerve cell), the concentration of K+ ions inside the cell is about 20 to 30 times greater than
that outside. What potential difference between the inside and the outside of the cell would you expect to
measure if the difference is due only to the imbalance of potassium ions?            (    )
A. 8V to 9V
B. +0.16V to +0.18V
C. +0.04V to +0.045V
D. +0.08V to +0.09V
E. +0. 8V to +0.9V
II. Fill in the following blanks with correct terms.
1. Calculate the pH of each of the following buffer solution,containing equal volumes of two solutes in the concentrations indicated
(a) 0.6mol·L -1 NH 3, 0.6 mol·L -1 NH 4Cl            Answer: (1) .
(b) 0.25 mol·L -1H 3PO 4, 0.15 mol·L -1NaH 2PO 4      Answer: (2) .
2. Some reaction rate constant k=1L·mol -1 ·min -1, this reaction is  (3)  order reaction, when the beginning concentration of reactants is 0.1 mol.L -1, its half-life is T 1/2=  (4) .
3..Put phenothalin in the ammonia , the aqua turn to  (5) . if the solid of NH 4Cl is joined,  the color of aqua will become  (6) , this is the cause of (7) .
III. True or False
1. According to the proton theory of acid and base, the −4
2PO H  is acid.  （  ） 2.At any state, when the reaction attains balance, △Ｇ=
0.            （  ） 3. All coordination compound can be divided into inside and external two parts of boundary.（  ）
reaction order4. The saturated solutions are all the strong solution.                        （  ）
5. The carbon atom in CCl 4 is equivalent hybridization sp 3 , so it is nonpolar molecule. （  ） IV. Answer questions in brief
1. (1) Give the conjugate base to each of the following species regarded as acids.
(a) −4HSO    (b) H 2S    (c) −4
2PO H    (d) +4NH  (2).Give the conjugate acid to each of the following species regarded as bases.
(a) CN -      (b) -3HCO    (c) 2-4
SeO    (d) 3-4PO  2. The methyl ether and ethanol have the same chemical formula, but their boiling points are different. Why?
V. Calculation
1. Consider the galvanic cell Pt(s)|Sn 4+(0.010 mol ⋅L -1), Sn 2+(0.10 mol ⋅L -1)|| (aq, pH = 4.00)|O 2 (g, 100KP a )|C(gr)
(1) What is the standard cell emf (electromotive force)?
(2) Write the cell reaction.
(3) Calculate the actual cell emf.
(4) Determine the equilibrium constant of the cell reaction.
(5) Calculate the free energy of the cell reaction.
2、The freezing point that 4.28g of substance is dissolved in 0.100L of water is equal to that 1.50g of carbamide is dissolved in 0.200L of water. What is the molar mass of the substance ?( carbamide M  =60.05, K f  (H 2O)=1.86)
【英文综合测试题参考答案】
I. 1. A  2. C  3. A  4. B  5. D
II.
1．(1) 9.26  (2) 1.99
2．(3) second  (4) 10 min.
3. (5) red.  (6) shallow  (7) the common-ion effect.
III.
1. F
2. T
3. F
4. F
5. T
Ⅳ.
1. (1)(a) −2
4SO    (b) HS -    (c) −24HPO    (d) NH 3
(2). (a) HCN    (b) H 2CO 3  (c) HSeO 4-    (d) HPO 42-
2. The structure of the methyl ether and ethanol are different, the ethanol has hydrogen bond and the methyl ether has not. The bond energy of ethanol is stronger than van der Waals force.
V.
1. (1) E θ=1.229 V -0.151 V =1.078V
(2) O 2(g) + 4H +(aq)+ 2Sn 2+(aq) = 2Sn 4+(aq)+ 2H 2O(l) (3) p q c c n ）（Ox Red θ
)(lg V 05916.0)Ox/Red ()Ox/Red (−=ϕϕ 44
220.05916V (10)(O /H O)  1.229V lg 0.9924V 41
ϕ−=+= 4++2+0.05916V 0.01(Sn /Sn )0.151V lg 0.1214V 20.1
ϕ=+=  E =0.9924 V -0.1214 V =0.871V (4) θθ((Ox/Red (Ox/Red))lg 72.88V 0.05916
n K ϕϕ+−−= K =7.6×1072
(5) Δr G m =-nFE =-3.4×102
2. B f B B A
Δf m T Kb K M m == )carbamide  (ΔT )(ΔT f f =x
20005.6050.110028.4x x x ×=M  M (X) = 343(g·mol -1)

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