c#jobject的数据结构的解析：c# jobject 数据结构的解析：
⾸先下载Newtonsoft.Json，增加引⽤using Newtonsoft.Json.Linq;
把jobject的内容提取出来，Jobject的内容格式如下:
{
"code": 200,
"msg": "SUCCESS",
"data": {
"id": "12345678",
"name": "张三",
"sex": "男",
"result": {
"access_token": "49d58eacd7811e463429a1ae10b42173",
"user_info": [{
"school": "社会⼤学",
"major": "软件开发",
"education": "本科",
"score": 97
}, {
"school": "湖南⼤学",
"major": "软件⼯程",
"education": "研究⽣",
"score": 100
}]
}
}
}安卓在线解析json
可放到json官⽹在线JSON校验格式化⼯具⾥解析。
代码如下：
1，新建类：
public class UserInfo
{
public string id { get; set; }
public string name { get; set; }
public string sex { get; set; }
public string access_token { get; set; }
public string school { get; set; }
public string major { get; set; }
public string education { get; set; }
public string score { get; set; }
}
2，获取值：
JObject result = new JObject();//假设result为数据结构
UserInfo userinfo = new UserInfo();
userinfo.id = result["data"].Value<string>("id");//id
userinfo.name = result["data"].Value<string>("name"); //name
userinfo.sex = result["data"].Value<string>("sex"); //sex
userinfo.access_token= result["data"]["result"]["access_token"].ToString();//access_token
JArray res = result["data"]["result"].Value<JArray>("user_info");
JObject obj = JObject.Parse(res[0].ToString());//只获取数据结构中第⼀个userinfo⾥的数据信息            userinfo.school = obj.Value<string>("school"); //schoool
userinfo.major = obj.Value<string>("major");//major
userinfo.education = obj.Value<string>("education");//education
userinfo.score= obj.Value<string>("score");//score

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