vb 多项式回归代码
以下是一个使用VB语言实现多项式回归的代码示例：array在vb什么意思啊
```vb
Imports System
Imports System.Collections.Generic
Imports System.Linq
Imports System.Text
Imports System.Threading.Tasks
Module Program
    Sub Main(args As String())
        ' 输入数据
        Dim xValues As Double() = {1, 2, 3, 4, 5}
        Dim yValues As Double() = {3, 5, 7, 9, 11}
        ' 多项式回归的阶数
        Dim degree As Integer = 2
        ' 创建多项式回归模型
        Dim regression As New PolynomialRegression(degree)
        ' 训练模型
        regression.Train(xValues, yValues)
        ' 预测新数据
        Dim newXValue As Double = 6
        Dim newYValue As Double = regression.Predict(newXValue)
        Console.WriteLine("预测值: " & newYValue)
        Console.ReadLine()
    End Sub
End Module
Public Class PolynomialRegression
    Private degree As Integer
    Private coefficients As Double()
    Public Sub New(degree As Integer)
        Me.degree = degree
    End Sub
    Public Sub Train(xValues As Double(), yValues As Double())
        Dim n As Integer = xValues.Length
        Dim matrix As New Matrix(n, degree + 1)
        Dim vector As New Vector(n)
        For i As Integer = 0 To n - 1
            Dim x As Double = xValues(i)
            Dim y As Double = yValues(i)
            For j As Integer = 0 To degree
                matrix(i, j) = Math.Pow(x, j)
            Next
            vector(i) = y
        Next
        Dim q As New QRDecomposition(matrix)
        Dim b As Vector = q.Solve(vector)
        coefficients = b.ToArray()
    End Sub
    Public Function Predict(xValue As Double) As Double
        Dim result As Double = 0
        For i As Integer = 0 To degree
            result += coefficients(i) * Math.Pow(xValue, i)
        Next
        Return result
    End Function
End Class
Public Class Matrix
    Private data As Double(,)
    Public Sub New(rows As Integer, columns As Integer)
        data = New Double(rows - 1, columns - 1) {}
    End Sub
    Public Property Item(row As Integer, column As Integer) As Double
        Get
            Return data(row, column)
        End Get
        Set(value As Double)
            data(row, column) = value
        End Set
    End Property
    Public Function GetLength(dimension As Integer) As Integer
        Return data.GetLength(dimension - 1)
    End Function
End Class
Public Class Vector
    Private data As Double()
    Public Sub New(size As Integer)
        data = New Double(size - 1) {}
    End Sub
    Public Property Item(index As Integer) As Double
        Get
            Return data(index)

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