c语⾔数组打印字符串,C语⾔打印循环中的数组字符串
OK，我会建议你做⼀些更有效的，并且是使⽤双指针。通过这样做，您可以解决2D阵列版本中存在的⼀些问题。
第⼀个问题是，如果⽤户想要插⼊超过999个糖果，你会怎么做。你的数组不能容纳它们。
其次，如果⽤户输⼊⼤于100个字符的名称，你会怎么做。再⼀次，你的⼆维数组不能容纳它。⽽且，尽管⽤户可能输⼊⼤于100个字符的名称，但⼤多数⽤户的输⼊会⽐这个少得多，现在对于每个字符串，当您可能只需要⼤约50个时，就会分配100个位置。
因此，让我们来处理这些问题。 我可能会做这样的事情：
#include
#include // for strcpy(), strlen()
#include // for malloc()
int main(void) {
char **sweet_names; // make a double pointer(or you might see that as array of pointers
char reader[300]; // this variable will help us read every name into the sweet_names
int sweet_number;
int i, j;
// Your code here to get the number of sweet_names
/*Prompts the user to enter the number of sweets and saves it to sweet_number*/
printf("Please enter the number of sweets:\n");
scanf("%d", &sweet_number);
// Now that you know the sweet_number, allocate as much memory as you need.
// And that can be more than 999 sweet names
sweet_names = (char **) malloc(sweet_number * sizeof(char *));
/
/ i.e. make a character pointer to sweet_number character pointers.
// Again, some of your code here
for (i = 0; sweet_number > i; i++) {
printf("What is the name of the sweet?\n");
scanf("%s", reader); // read into the reader
sweet_names[i] = (char *) malloc(strlen(reader) + 1); // allocate as much memory as you need for the current string, the one just read into reader
strcpy(sweet_names[i], reader); // copy contents of reader to sweet_names[i]
}
// Again, your code to print the names
for (j = 0; sweet_number > j; j++){
printf("%s\n", sweet_names[j]);
free(sweet_names[j]); // free every string you allocated, it is good practice
}
c语言如何创建字符串数组
// Finally, free the sweet_names pointers. Generally, when you allocate
// dynamically, which is what we do with malloc(), it is a good practice
// to free what you allocate becuase otherwise stays in memory and then
// memory leaks are created. There is a lot to say about C and memory
// but anyway, remember to free
free(sweet_names);
return 0;
}
最后，现在程序再次有限制只读名最多，因为reader 300个字符，但这个东西，你也可以处理，⽽这是为读者分配⼀个疯狂的内存量，如1000000 个字符，然后释放它。

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