注意:这是04-05学期王老师出的试题。
1.Ethernet使用的MAC协议是(1)。当发生冲突时,将进入二进制指数退避阶段,对于第3次冲突,等待重传的最长时间是512位时间的(2)倍。
(1)A.ALOHA B.CSMA/CD C.CSMA/CA D.CSMA/DD
(2)A.1 B.3 C.5 D.7
2.网络体系结构定义计算机网络的分层结构,TCP/IP模型和ISO/OSI参考模型是两个主要的网络模型,其中TCP/IP协议传送层之上的层是(3)层,而ISO/OSI则是一个 (4) 层的模型。
(3)A.应用 B.表述 C.会话 D.网络
(4)A.4 B.5 C.6 D.7
tcp ip协议各自的含义是什么3.传统的以太网传输介质是同轴电缆,其中使用粗同轴电缆的网络称为(5)网络,使用细同轴电缆的网络称为(6)网络。10Base-T网络使用的传输介质是无屏蔽双绞线,简称为 (7)。
(5)A.5BASE B.10BASE-10 C.10BASE-5 D.10BASE-2
(6)A.5BASE B.10BASE-10 C.10BASE-5 D.10BASE-2
(7)A.UPT B.UTP C.UPP D.UUP
4.有N个节点共享一条总传输速率为R的通信信道,若采用TDMA协议,则每个节点的平均传输速率是 (8) ,而瞬时传输速率则为 (9);如果采用FDMA协议,则每个节点的平均传输为 (10),而瞬时传输速率则为 (11) 。
(8)A.R B.R/N C.NR D.2R
(9)A.R B.R/N C.NR D.2R
(10)A.R B.R/N C.NR D.2R
(11)A.R B.R/N C.NR D.2R
5.可靠传输协议rdt3.0的发送和接收窗口都是1,对其进行改进后的GBN协议和SR协议都把
发送窗口尺寸扩大为N(>1)。但GBN协议的接收窗口为(12),而SR协议的接收窗口为(13)。对SR协议,若使用k位的序号,则其发送窗口尺寸应 (14) 。
(12)A.1 B.N/4 C.N/2 D.N
(13)A.1 B.N/4 C.N/2 D.N
(14)A.不大于2k B.等于2k C.不大于2k-1 D.等于2k-1
6.PPP协议可以用在(15) 链路上,并使用 (16)协议完成链路状态的管理,使用 (17)协议完成网络层地址配置和压缩方式协商。
(15)A.多点对多点 B.点对点 C.点对多点 D.任何
(16)A.CNP B.PLC C.LCP D.NCP
(17)A.CNP B.PLC C.LCP D.NCP
7.RTP协议和RTCP协议是TCP/IP协议的(18)层的扩充子层,H.323是 (19) 层协议。
(18)A.应用层 B.传送层 C.网络层 D.链路层
(19)A.应用层 B.传送层 C.网络层 D.链路层
8.在以太网中,增加帧的尺寸将使信道利用率 (20)。
(20)A.提高 B.降低 C.保持恒定 D.无法断定
二、Match the following tasks to one of the TCP/IP layers: (10%)
1. Route determination ( 网络层 )
2. Transmission of Segment ( 运输层 )
3. ASCII changed to EBCDIC (链路层 )
4. Frame defined ( 链路层 )
5. Transmission of data frame ( 链路层 )
6. Provides log-in and logout procedures (应用程 )
7. Selects a destination network (网络层 )
8. Provides services for the network applications (应用层 )
9. Reliable end-to-end data transmission (运输层 )
10. Provides E-mail and file transfer services (应用程 )
三、Answer the following questions (20%):
(1)Please show an example for every IP V4 address classes. (5%)
A类地址范围(0.0.0.0----127.255.255.255)
B类地址范围(128.0.0.0----191.255.255.255)
C类地址范围(192.0.0.0----223.255.255.255)
D类地址范围(224.0.0.0----239.255.255.255)
E类地址范围(240.0.0.0----255.255.255.255)
(2)Consider IP address 202.203.208.68 . What are the broadcast address and network address when default network mask is used? (5%)
broadcast address :202.203.208.255
network address :202.203.208.0
(3)What are the format and example of IPv6 address?(5%)
(4) Consider plain text “thisisatest” , and the Caesar cipher of k=4 is used. What is the Cipher text after encrypting? (5%)
四、Complete follow problems. (35%)
1. Suppose we want to transmit the message 10101001 and protect it from errors using the CRC generator x3+1. Use long division to determine the message that should be transmitted.(10%)
2. Consider a CSMA/CD network running at 100Mbps, over a 1000m cable with no repeate
rs. The signal speed in the cable is 2×108m/sec. What is the minimum frame size for check collision reliably? (10%
3. Suppose two Ethernet nodes of 10Mbps, A and B, are attached to opposite ends of a 900m cable, and there are 4 repeaters between A and B. If the size of frame is 1000 bits, and the signal propagation speed is 2×108m/s, and each repeater inserts 20-bit delay. (15%)
(1) What is the one-way propagation delay (including repeater delays) between A and B in second ?
(2) How long time is node A’s a frame completely delivered at node B?
五、 Consider a LAN shown below and one class C address 202.1.0.0/24 is available only. Please accomplish the following questions: (15%)
(1) Assign IP Network number and netmask for all LANs.
(2) Assign IP addresses to
all network interfaces .
(3) Determine the route table
on router R1.
Answer:
(1)网络地址分配
网络 | 网络地址 | 网络掩码 |
A、B、R1-1 | 202.1.1.0/26 | 255.255.255.0 |
C、D、R1-2 | 202.1.1.64/26 | 255.255.255.0 |
R1-3、R2-1 | 202.1.1.128/26 | 255.255.255.0 |
E、F、R2-2 | 202.1.1.192/26 | 255.255.255.0 |
(2)端口IP地址分配
端口 | IP地址 | 端口 | IP地址 | 端口 | IP地址 |
A | 202.1.1.2 | C | 202.1.1.65 | E | 202.1.1.193 |
B | 202.1.1.1 | D | 202.1.1.66 | F | 202.1.1.194 |
R1-1 | 202.1.1.63 | R1-2 | 202.1.1.126 | R2-2 | 202.1.1.254 |
R1-3 | 202.1.1.190 | R2-1 | 202.1.1.189 | ||
(3)R1上的路由表
Dest. Network | next router | N hops | Interface |
三、Answer follow questions.(20%)
(1)How big is the Ethernet address space? The IPv4 address space? (5%)
(2)Compare and contrast link-state and distance-vector routing algorithm.(5%)
版权声明:本站内容均来自互联网,仅供演示用,请勿用于商业和其他非法用途。如果侵犯了您的权益请与我们联系QQ:729038198,我们将在24小时内删除。
发表评论